x^2-7.96x+3.12=0

Solution for x^2-7.96x+3.12=0 equation:

x^2-7.96x+3.12=0

a = 1; b = -7.96; c = +3.12;
Δ = b2-4ac
Δ = -7.962-4·1·3.12
Δ = 50.8816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7.96)-\sqrt{50.8816}}{2*1}=\frac{7.96-\sqrt{50.8816}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7.96)+\sqrt{50.8816}}{2*1}=\frac{7.96+\sqrt{50.8816}}{2}
$